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Secondary Transformer-Current Type Voltage Transformer
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Product description
Parameters
Usage
*Occasion of use: Generally used in instruments and meters with high space requirements for testing voltage, electric energy and power;
*Principle of use: Primary and secondary 2 mA: 2 mA current, primary series resistance, secondary parallel resistance test voltage;
*Product features: high test accuracy and small size.
Technical
*Withstand voltage rating:2 / 3 KV;
*Rated frequency:50 / 60 HZ;
*Flame retardant properties:UL 94 - V 0;
*Use environment:- 25℃-50℃。

Product specifications |
Iin |
Io |
Rb |
Overload multiple |
20%-120% |
|
|
|
|
|
|
F |
|
TV/A2-2E |
2mA |
2mA |
100 |
4 |
0.2 |
30 |
HPT225A |
2mA |
2mA |
100 |
4 |
0.2 |
30 |
TV/A2-2C |
2mA |
2mA |
100 |
6 |
0.1 |
30 |
typical application
Case1:
The typical application circuit is shown in Figure 1, and the secondary load is basically zero. The measured input voltage VIN is limited by the current limiting resistor RIN, and the generated 0-2 mA current passes through the miniature voltage transformer. The transformer senses the same 0-2 mA through the operational amplifier
, The user can adjust the value of the feedback resistor R to get the required voltage output at the output. The capacitor C and resistor r are used to compensate the phase difference. If the user uses software compensation or does not need to compensate the phase difference, the capacitor C and the resistor r can be disconnected. The operational amplifier in the figure is a general-purpose operational amplifier. The accuracy of the feedback resistor R and the current limiting resistor RIN are related to the accuracy requirements of the output voltage, D 1
, D 2 diode is 1 N 4148 for protection. C 0 is an anti-interference capacitor, which is determined according to the user's circuit and operational amplifier technical parameters, otherwise it will cause the output signal to oscillate. The current limiting resistor RIN is selected as RIN= VIN/ 2 m A- r 0 (internal resistance of the transformer)。

Case2:
Figure 2 shows the direct output circuit of parallel resistor R. The resistor R is not more than 500 ohms (the output voltage is 1.0 V maximum), and the secondary load is R. The phase difference of the direct output circuit becomes larger due to the large load, and the linearity becomes worse. Suitable for occasions with low requirements. C in Figure 2 can play a role in phase compensation, and it can be omitted if there is no phase requirement. The compensation amount RIN is selected RIN= VIN/ 2 m A- r 0 (internal resistance of the transformer:Δδ= - 100 π CR× 3438 ’。
mount
The narrow leg is a winding, input and output are not distinguished, and can be blind inserted;
Order requirements
You only need to choose the size, shape and overload multiple to choose the model. If you have special needs, you can customize。
mount
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